Webb4680 – 17 = 4663. ∴ 4663 should be the smallest number which, when increased by 17, is exactly divisible by both 520 and 468. 9. Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32, respectively. Solution: First, let’s find the smallest number, which is exactly divisible by both 28 and 32. WebbAnswer: 4663 is the smallest number which when increased by 17 is exactly divisible by both 520 and 468. Let's explore the least common multiple and how to apply LCM to the …
Write the smallest number which is divisible by bo - Tutorix
Webb4 feb. 2024 · Step 1: Begin by writing the numbers in a horizontal line separated by commas. Step 2: Next, divide all of the numbers given by the smallest prime number. … WebbEditors select a small number of articles recently published in the journal that they believe will be particularly interesting to readers, ... [17,18]. The greenhouse increased the temperature during the daytime but was only able to maintain an acceptable nighttime temperature when insulation was used in the construction. t shirt luggage cover
LCM Questions and Answers - PREP INSTA
Webbför 2 dagar sedan · Consumer prices overall increased 5% from a year earlier, ... That’s the smallest annual gain since May 2024. ... gas prices declined 4.6% and are down 17.4% … Webb23 apr. 2024 · Hi All, This question includes a number of great Number Property shortcuts that you can take advantage of: 1) The question asks for the SMALLEST number that, when increased by 5 is divisible by 8, 11 and 24. Since the answers are numbers, we can TEST THE ANSWERS. 2) Any number that is divisible by 24 is ALSO divisible by 8, so we really … WebbLCM = product of greatest power of each prime factor involved in the numbers = 22 × 32 × 5 × 13 = 4680 . The required number is 4680 – 17 = 4663. Hence, the smallest number which when increased by 17 is exactly divisible by both 468 and 520 is 4663. t shirt luffy roblox png