Web18 feb. 2015 · How many terms of the a.p. 48,42,36,.... be taken so that the sum is 216? How many terms of the a.p. 48,42,36,.... be taken so ... person. Raghunath Reddy. According to the given AP ,a = 48 & d = - 6 and sum of the given AP = 216. we know that S n = n/2(2a + (n -1)d) 216 = n/2(2(48) + (n -1)-6) => 432 = n(96 - 6n + 6) => 432 = 102n ... WebFind the number of terms of the. AP 54, 51, 48, ...... so that their sum is 513. Explain the double answer. Question Medium Solution Verified by Toppr a=54 d=51−54=−3 S n=513 S n= 2n[2a+(n−1)d] ⇒513= 2n[2(54)+(n−1)(−3)] ⇒1026=n[108−3n+3] ⇒1026=n[111−3n] …
find how many term of the AP.54,51,48...must be taken so that …
WebClick here👆to get an answer to your question ️ \"How many terms of the series \\( 54,51,48 \\). Whin be taken so that,\ntheir sum is 513 ? Explain the double answer\" Web28 mrt. 2024 · Ex 5.3, 4 - Chapter 5 Class 10 Arithmetic Progressions (Term 2) Last updated at March 28, 2024 by Teachoo. This video is only available for Teachoo black … photo app on windows 10
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WebAnswer (1 of 5): In the above AP series it is given that Sn = 513 a = 54 d = (-3) n = ? We know Sn = n/2(2a+(n-1) d) Therefore 513 =n/2(2×54) +(n-1) (-3) 1026 = n(108-3n+3) =108n-3n^2+3n 3n^2-108n-3n+1026 = 0 Dividing above equation by 3 n^2-36n-n+342 = 0 n^2-37n+342 = 0 n^2–18n-19n... Web31 mrt. 2024 · nth term of AP = 0 The given AP = 54, 51, 48 … Formula: T n = a + (n – 1)d Where, a = first term and d = common difference Calculation: Here, a = 54 d = 51 – 54 = - 3 T n = a + (n – 1) d ⇒ 0 = 54 + (n – 1) × (- 3) ⇒ (n – 1) × (-3) = - 54 ⇒ n – 1 = 54/3 ⇒ n – 1 = 18 ⇒ n = 19 ∴ There are 19 terms of the AP. Download Solution PDF Share on Whatsapp WebHow many terms of the AP: 9, 17, 25, … must be taken to give a sum of 636? ... Find the number of terms of the AP: 54, 51, 48, … so that their sum is 513. 60. In an AP, the first term is –4, the last term is 29 and the sum of all its terms is … photo app on microsoft store